Help! If you know this can you tell me how to do it?

Answer:cStep-by-step explanation:Here's how this works:Get everything together into one fraction by finding the LCD and doing the math.  The LCD is sin(x) cos(x).  Multiplying that in to each term looks like this:[tex][sin(x)cos(x)]\frac{sin(x)}{cos(x)}+[sin(x)cos(x)]\frac{cos(x)}{sin(x)} =?[/tex]In the first term, the cos(x)'s cancel out, and in the second term the sin(x)'s cancel out, leaving:[tex]\frac{sin^2(x)}{sin(x)cos(x)}+\frac{cos^2(x)}{sin(x)cos(x)}=?[/tex]Put everything over the common denominator now:[tex]\frac{sin^2(x)+cos^2(x)}{sin(x)cos(x)}=?[/tex]Since [tex]sin^2(x)+cos^2(x)=1[/tex], we will make that substitution:[tex]\frac{1}{sin(x)cos(x)}[/tex]We could separate that fraction into 2:[tex]\frac{1}{sin(x)}[/tex]×[tex]\frac{1}{cos(x)}[/tex][tex]\frac{1}{sin(x)}=csc(x)[/tex]  and  [tex]\frac{1}{cos(x)}=sec(x)[/tex]Therefore, the simplification issec(x)csc(x)