passes through A(-3, 0) and B(-6, 5). What is the equation of the line that passes through the origin and is parallel to ?

Answer:        Equation of line , 5x + 3y = 0Step-by-step explanation:The slope of a line passing through points (x₁,y₁) and (x₂,y₂) is given by [tex]\frac{y_2-y_1}{x_2-x_1}[/tex]Here points are given by (-3,0) and (-6,5)Slope[tex]=\frac{5-0}{(-6)-(-3)}=\frac{-5}{3}[/tex]The slope of parallel lines are same. So slope of required line [tex]=\frac{-5}{3}[/tex]Equation of a line with slope m passing through origin is given by                     y =mx                So equation of line, [tex]y=\frac{-5}{3}x\\\\3y=-5x\\\\5x+3y=0[/tex]Equation of line , 5x + 3y = 0